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66y^2+342y-560=0
a = 66; b = 342; c = -560;
Δ = b2-4ac
Δ = 3422-4·66·(-560)
Δ = 264804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{264804}=\sqrt{4*66201}=\sqrt{4}*\sqrt{66201}=2\sqrt{66201}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(342)-2\sqrt{66201}}{2*66}=\frac{-342-2\sqrt{66201}}{132} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(342)+2\sqrt{66201}}{2*66}=\frac{-342+2\sqrt{66201}}{132} $
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